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x in (-oo:+oo)
-(((6*x-5)^2+8)/(3^2)) = 0
(-1*((6*x-5)^2+8))/9 = 0
(6*x-5)^2+8 = 0
(6*x-5)^2+8 = 0
36*x^2-60*x+33 = 0
36*x^2-60*x+33 = 0
3*(12*x^2-20*x+11) = 0
12*x^2-20*x+11 = 0
DELTA = (-20)^2-(4*11*12)
DELTA = -128
DELTA < 0
3 = 0
3 = 0
(-1*3)/9 = 0
x belongs to the empty set
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